HackerEarth: Kinako Bread (DS- Greedy, 2 pointers )

HackerEarth: Kinako Bread (DS- Greedy, 2 pointers )

///==================================================/// /// HELLO WORLD !! /// /// IT'S ME /// /// BISHAL GAUTAM /// /// [ bsal.gautam16@gmail.com ] /// ///==================================================/// #include<bits/stdc++.h> #define X first #define Y second #define mpp make_pair #define nl printf("\n") #define SZ(x) (int)(x.size()) #define pb(x) push_back(x) #define pii pair<int,int> #define pll pair<ll,ll> ///--------------------- #define S(a) scanf("%d",&a) #define P(a) printf("%d",a) #define SL(a) scanf("%lld",&a) #define S2(a,b) scanf("%d%d",&a,&b) #define SL2(a,b) scanf("%lld%lld",&a,&b) ///------------------------------------ #define all(v) v.begin(),v.end() #define CLR(a) memset(a,0,sizeof(a)) #define SET(a) memset(a,-1,sizeof(a)) #define fr(i,a,n) for(int i=a;i<=n;i++) using namespace std; typedef long long ll; ///==========CONSTANTS=============/// /// Digit 0123456789012345678 /// #define MX 100005 #define inf 1000000010 #define MD 1000000000LL #define eps 1e-9 ///===============================/// vector<int>v[MX+2]; int L[MX+2],R[MX+2]; int c1[MX+2],c2[MX+2];///Connections- Least connection & Most connections; set<pii>sl,sr;/// storing current indices of Least & most for every elements ll Calc( ) { int rgBg=(*sr.begin()).X; int lfEd=(*sl.rbegin()).X; return (rgBg-lfEd); } int s[MX+2]; int ar[MX+2]; int main() { int tc,cs=1,i,j,k,q,n,m,x,y; //S(tc); tc=1; while(tc--) { S2(n,m); fr(i,1,m)v[i].clear(); fr(i,1,n) { S(x); ar[i]=x; v[ x ].pb( i ); } fr( i,1,m ) { S2( L[i],R[i] ); R[i]++; } int i,f=1; sl.clear(); sr.clear(); CLR(s);/// s-arry for tot times 'i' has been taken /// Pre; for(i=1; i<=m; i++) { int sz=SZ( v[i] ); if( L[i]+s[i]>sz ) { f=0; break; } else c1[ i ]=v[i][ L[i]+s[i]-1 ]; if( R[i]+s[i]>sz ) { c2[i]=n+1; } else c2[i]=v[i][ R[i]+s[i]-1]; sl.insert( mpp( c1[i],i ) ); sr.insert( mpp( c2[i],i ) ); s[i]++; } if(f==0) { printf("0\n"); continue; } ll tp=max( Calc( ),0LL ); /// Now, Procedure of deleting from last; ll sm=tp; int j=1; while(j<=n) { i=ar[j]; ///Del ar[i] && update latest info for ar[i]; sl.erase( mpp( c1[i],i ) ); sr.erase( mpp( c2[i],i ) ); int sz=SZ( v[i] ); if( L[i]+s[i]>sz ) { break; } else c1[ i ]=v[i][ L[i]+s[i]-1 ]; if( R[i]+s[i]>sz ) { c2[i]=n+1; } else c2[i]=v[i][ R[i]+s[i]-1]; sl.insert( mpp( c1[i],i ) ); sr.insert( mpp( c2[i],i ) ); s[i]++; ll tp=Calc(); sm+=max( tp,0LL ); j++; } printf("%lld\n",sm); } return 0; }

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